A human bone is subjected to a compressive force of 5.0×10^5 N. The bone is 25 cm long and has approximate cross sectional area of 4.0 cm^2. If the ultimate compressive strength of the bone is 1.70×10^8 N/m^2, will the bone be compressed or it will break under this force ?

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Arun · Answer

Stress = F/A = 5 * 10^5/ 4 * 10^-4 = 12.5 * 10^8 Since this stress exceeds the ultimate compressive stress of the bone, Hence bone will break. Regards Arun (askIITians forum expert)

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A human bone is subjected to a compressive force of 5.0×10^5 N. The bone is 25 cm long and has approximate cross sectional area of 4.0 cm^2. If the ultimate compressive strength of the bone is 1.70×10^8 N/m^2, will the bone be compressed or it will break under this force ?

A human bone is subjected to a compressive force of 5.0×10^5 N. The bone is 25 cm long and has approximate cross sectional area of 4.0 cm^2. If the ultimate compressive strength of the bone is 1.70×10^8 N/m^2, will the bone be compressed or it will break under this force ?

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A human bone is subjected to a compressive force of 5.0×10^5 N. The bone is 25 cm long and has approximate cross sectional area of 4.0 cm^2. If the ultimate compressive strength of the bone is 1.70×10^8 N/m^2, will the bone be compressed or it will break under this force ?

A human bone is subjected to a compressive force of 5.0×10^5 N. The bone is 25 cm long and has approximate cross sectional area of 4.0 cm^2. If the ultimate compressive strength of the bone is 1.70×10^8 N/m^2, will the bone be compressed or it will break under this force ?

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