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A heavy ring of mass m is clamped on the periphery of a light circular disc. A small particle having equal mass is clamped at the centre of the disc. The system is rotated in such a way that the centre moves in a circle of radius r with a uniform speed v. We conclude that an external force

A heavy ring of mass m is clamped on the periphery of a light circular disc. A small particle having equal
mass is clamped at the centre of the disc. The system is rotated in such a way that the centre moves
in a circle of radius r with a uniform speed v. We conclude that an external force

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1 Answers

Mihir
33 Points
5 years ago
Answer is just simple.
2mv^2/r .
Must be acting on the system
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 

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