A glass filled with water upto 12.5cm. The appare

Question

A glass filled with water upto 12.5cm. The apparent of an object lying at the bottom of the glass is measured by a microscope to be 9.4m. Calculate the refractive index of water.If water is replaced by a liquid of refractive index 1.63 upto the same height, by what distance would the microscope have to be moved to focus the object again?

Orooba Asim · Accepted Answer

Actual depth, h1 = 12.5 cmApparent depth, h2= 9.4 cmRefractive index n1= h1/h2= 1.33 Therefore nH2O = 1.33Refractive index of the other liquid is n’ = 1.63(Actual depth) h1= 12.5 bc it’s the same glass.Apparent depth h’ = h1/ n’ = 7.7 (approx.) and h’ 2 and thus the microscope should be moved upwards by a distance of h2 - h’ = 1.7 cm

General Physics> A glass filled with water upto 12.5cm. Th...

Rai , 8 Years ago

Orooba Asim

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General Physics> A glass filled with water upto 12.5cm. Th...

Rai , 8 Years ago

Orooba Asim

LIVE ONLINE CLASSES

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