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A force is inclined at 60° to the horizontal.If its rectangular component in the horizontal direction is 50N, then magnitude of the force in the vertical direction is? (Plz give complete sol.)

A force is inclined at 60° to the horizontal.If its rectangular component in the horizontal direction is 50N, then magnitude of the force in the vertical direction is? (Plz give complete sol.)

Grade:11

2 Answers

Ravneet
104 Points
5 years ago
horizontal component of force = fcos60 = 50N ---------------------(1)
vertical component of force = fsin60
usinf equation 1 , we get f = 100N 
now , put the value of f in vertical component
vertical component = 100 X 31/2/2 = 100 X 0.866 = 86.6 N
Venkat
273 Points
5 years ago
Given that the force is inclined at 60° from the horizontal and  the horizontal component is 50.
Let the force be F . Therefore the force is given by.....
F x cos 60° = 50
F = 50 x 2
F = 100 units
 
The vertical component of the force is given by,
F x sin 60° =  vertical component
vertical component = 100 x √3/2
                               = 173.2/2
                               = 86.6 units
 

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