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Grade: 11
        a force F1 of 500 newton is required to push a car of mass 1000 kg slowly at a constant speed on a level road If force F2 of 1000 newton is applied the acceleration of the car will be
one year ago

Answers : (2)

Diwankar singh
17 Points
							In first case:Force=500NMass=1000kg Therefore,                 F=m*a              So,    a=F/m                        a=500/1000                         a=0.5m^2 In second case:    Force=1000N    Mass=1000kg               a=F/m                a=1000/1000                  a=1m^2
						
one year ago
Sahil
15 Points
							
Sice 500N of force is required to move the car with cosntant speed so out of 1000N , 500N of force will lost in moving the car with constant speed and the remaining 500N will provide acceleration . So
By the equation -- F=ma 
                             500=1000a 
                              a = 0.5 m/s
10 months ago
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