A food packet was dropped from an aircraft flying horizontally.6s before it hit the ground,it was at a height of 780m,and had travelled a distance of 1km horizontally.Find the speed and the altitude of the aircraft.

Height of the fighter plane = 1.5 km = 1500 mSpeed of the fighter plane, v = 720 km/h = 200 m/sLet θ be the angle with the vertical so that the shell hits the plane.Muzzle velocity of the gun, u = 600 m/sTime taken by the shell to hit the plane = tHorizontal distance travelled by the shell = uxtDistance travelled by the plane = vtThe shell hits the plane. Hence, these two distances must be equal.uxt = vt usinΘ = vsinΘ = v/usinΘ = 200/600 = 1/3Θ = sin-1(0.33)Θ = 19.5 degrees