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A ELASTIC SPHERE INITIALLY HAS ADIAMETER OF 1.1 M AND CONTAINS A GAS AT A PRESSURE OF 1.1ATM .DUE TOHEAT TRANSFER DIAMETER OF THE SPHERE INCREASE TO 1.2 M. DURING THE HEATING PROCESS THE GAS PRESSURE INSIDE THE SPHERE ISW PROPOTIONAL TO SPHERE DIAMETER .CALCULATE THE WORK DONE BY THE GAS IN KJ.

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8 months ago

```								pressure =p	Diameter =d	radius = r	constant = k	1atm = 1.013×10^5Given,    d1= 1.1m  , r1= 0.55m    d2 =1.2m. , r2= 0.6m    P1 =1.1×1.013×10^5 = 1.1143×105    Pressure is proportional to diameter ;           p=kd  or p= kr ie p/r=constant          1.1143×105/0.55 = p2/0.6          P2 =1.215×105            P and. r a ee relates as                     p=2r   The world done is pressure volume work hence             W =∫pdv     V is the volume of sphere                      v=(4/3)πr3.  dv =4πr2      W = ∫p4πr2. =∫2r×4πr2       =8π∫r3  = 2×3.14 [r4].6.55      =6.28×[(.6)4-(.55)4]. =0.239        Work = 0.239j
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6 months ago
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