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A disc of mass m and radius R is attached to a rectangular plate of the same mass breadth R and length 2R . Find moment of inertia of this system about diameter of of disc.They are attached about thier ends. the disc is attached about rectangle length . with explanation pls
Ip=I (com) + Md2 ,p= moment of inertia of axis through p , parallel to centre of mass and at a distance d from centre of mass.Icom = M(R)2/6 for rectangular sheet of breadth R.Therefore , Taking p is the centre of disc and axis parallel to centre of mass of rectangular sheet axis, We get Ip=MR2/6+ M(3R/2)2 {AS DISTANCE BETWEEN COM OF RECTANGLE AND CIRCLE IS 3R/2} Therefore, Ip = 29MR2/12 Adding this to MR2/4 , we get 32MR2/12
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