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a catapult caonsists of two parallel rubberstrings each a length of 10cm and cross sectional area 10mm^2.when stretched by 5cm it can throw a stone of mass 100gm to a vertical height of 25m,youngs modulus of elasticity of rubber is
Use work energy theorum, First find velocity at the instant when the body is released using v=(2gh)^1/2.Since catapult has 2 strings then effective spring constant becomes (2k).(mv^2)/2=(2kΔx^2)/2Here k=YA/l.Y-youngs modulusA -AreaΔx-extensionl-length of each stringm-mass of objectv--velocity
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