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A car travelling at 108km/hr has its speed reduced to 36km/hr while travelling a distance of 200m. Its acceleration and time taken are?

A car travelling at 108km/hr has its speed reduced to 36km/hr while travelling a distance of 200m. Its acceleration and time taken are?

Grade:12th pass

2 Answers

Karan Naidu
24 Points
8 years ago
accleration=-25920 km/hr^2    time=10 seconds (approx)
erra akhil
208 Points
8 years ago
Dear Jaya,
v2 - u2= 2 a S   -------- eq.1
v=final velocity
u=initial velocity
a=accelerartion(in this case retardation)
S=distance travelled
On solving;
by converting given speeds which are in km/hr to m/s by multiplying the speeds by 5/18;
we get, accelaration=-2 m/s or -0.555km/hr.(- sign indicates retardation)
v = u + a t -------eq.2
t=time taken.
time taken = 10 sec on solving.
Approve if my answer helped you.
 

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