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`        A car moving at 40 km/h is to be stopped applying brakes in the next 4.0 m. If the car weighs 2000 kg what average force must be applied on it?please...`
3 years ago

jakira
43 Points
```							1 km = 1000 m, 1 h = 3600 s, 1 km/h = 1000/3600 = 5/18 m/s v = 40 * 5/18 = 100/9 This is approximately 11.1 m/s. vf^2 = vi^2 + 2 * a * d, vf = 0, d = 4 0 = (100/9)^2 + 2 * a * 4 a = -(100/9)^2 ÷ 8 This is approximately -15.432 m/s^2 Average force = mass * acceleration = 2000 * -(100/9)^2 ÷ 8 This is approximately -30,864 N.
```
3 years ago
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• Test paper with Video Solution
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• NCERT Solutions
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