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A car first move √2 km due northeast 2 km due north and finally 3km due east .then the total displacement of the car is.
A car first move √2 km due northeast 2 km due north and finally 3km due east .then the total displacement of the car is.

```
2 years ago

## Answers : (1)

Susmita
425 Points
```							Let the car be initially at origin.Travells north east means its trajectory is y=tan45xOr,y=xSo x2+x2=(root2)2=2or,2x2=2or,x=1. (We would not take x=-1 as it is not moving north west.)So y=1So after travelling root2 km north east,the car's coordinate is (1,1).Now the car moves 2km north.So the x coordinate remains unchanged and y coordinate increases by 2 km.So the car's coordinate after travveling north is (1,3).Now the car moves 3km east.so y coordinate does not change and x coordinate increases by 3km.so car's final coordinate is (4,3).So displacement is distance from origin to (4,3) that isRoot(42+32)=root(16+9)=root25=5 km
```
2 years ago
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