A bus starts from rest and covers distance of 200m and acquires a speed of 20m during this run. Its acceleration is?

Question

Arun · Answer

Third formula of laws of motion V² = u² + 2 *a*s Now 20² = 0² + 2 * a * 200 400 = 0 + 400 *a Hence a = 400/400 a = 1 m/sec²

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A bus starts from rest and covers distance of 200m and acquires a speed of 20m during this run. Its acceleration is?

A bus starts from rest and covers distance of 200m and acquires a speed of 20m during this run. Its acceleration is?

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A bus starts from rest and covers distance of 200m and acquires a speed of 20m during this run. Its acceleration is?

A bus starts from rest and covers distance of 200m and acquires a speed of 20m during this run. Its acceleration is?

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