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A bus start from rest with an acceleration 2 m/s^2.Show that,a man can never catch the bus if he is more than 25 m. behind it.
To catch the bus the Distance covered by both must be same.So, for Man distance covered = 10twhile for the bus, it will be S=ut+ at2/2So S=10t2/2So 10t=10t2/2so 10t2-20t=0this gives t=0 and t=2 sec So these are possible points
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