Dear Student,
Expect that d be the thickness of the board and a be the speeding up of the board
From the newton's third condition of movement
v2 = u2+ 2ad
On the off chance that we need to stop the shot then the last speed will be zero.
Furthermore, on the off chance that we utilized n boards to stop that shot,
That is,
0 = u2 +2nad
2nad = u2
n = u2/(- 2ad) - (1.)
As given in the inquiry, the speed is 1/20 speed
that is v = u – u/20
= 19u/20
Substitute it in newtons third condition
(19u/20)2 = u2 + 2ad
\361/400 u^2 = u^2 + 2ad
- 2ad = u^2(1 - 361/400)
- 2ad = u^2 * 39/400
Presently we need to substitute this incentive in condition (1.)
n = u^2/(u^2 * 39/400) = 400/39
Least number of boards = 400/39 = 11.
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)