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a bullet of mass 10g fired with an initial velocity of 500 ms -1 hits a 20 kg wooden block at rest and gets embedded into it. calculate the velocity of the block after impact. how much energy is lost in the collision?
Before collision mass of bullet m,speed v.After collision mass of bullet+block=m+M and speed V.From conservation of linear momentummv=(m+M)VOr,V=mv/(m+M)m=10 g=10/1000 kg=0.01kg,M=20 kg,v=500m/sSo V=0.25 m/sloss of kinetic enegy=(1/2)[mv2-(m+M)V2]=1249.4 JPlease approve if you are helped.
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