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Grade 9General Physics

a bullet fired from a gun was given by f equals to 600 - 2 into 10 ^ fees in Newtons and 30 seconds the falls on the budget becomes zero as soon as the Bala what is the average impulse imparted to the bullet

Profile image of Sai
6 Years agoGrade 9
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2 Answers

Profile image of Arun
6 Years ago
F = 600 - 2 * 10⁵t
0 = 600 - 2 * 10⁵ t
t = 600 / (2 * 10⁵)
t = 3 * 10⁻³ s
t = 3 milliseconds
Time taken by bullet to leave the barrel is 3 milliseconds
F.dt = (600 - 2* 10⁵t).dt
J = [600t - (2 * 10⁵ t²/2)]
J = [600*(3*10^-3) - (2 * 10^5 * (3 * 10^-3)^2 / 2)]
J = 0.9 Ns
Impulse imparted to bullet is 0.9 Ns
 
Profile image of Vikas TU
6 Years ago
Dear student 
Above ans is incorrect 
The force will become zero in amount of time 't'
so,
F =   600 - 200000t = 0
or
t = 600 / 200000
thus,
t = 3 x 10 -3 s
now, we know that
Impulse = ∫Fdt = ∫(   600 - 200000t ).dt
which gives us
I = 1.8 Ns
Hope this helps