MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 9
        
a bullet fired from a gun was given by f equals to 600 - 2 into 10 ^ fees in Newtons and 30 seconds the falls on the budget becomes zero as soon as the Bala what is the average impulse imparted to the bullet
 
3 months ago

Answers : (2)

Arun
23546 Points
							
F = 600 - 2 * 10⁵t
0 = 600 - 2 * 10⁵ t
t = 600 / (2 * 10⁵)
t = 3 * 10⁻³ s
t = 3 milliseconds
Time taken by bullet to leave the barrel is 3 milliseconds
F.dt = (600 - 2* 10⁵t).dt
J = [600t - (2 * 10⁵ t²/2)]
J = [600*(3*10^-3) - (2 * 10^5 * (3 * 10^-3)^2 / 2)]
J = 0.9 Ns
Impulse imparted to bullet is 0.9 Ns
 
3 months ago
Vikas TU
10083 Points
							
Dear student 
Above ans is incorrect 
The force will become zero in amount of time 't'
so,
F =   600 - 200000t = 0
or
t = 600 / 200000
thus,
t = 3 x 10 -3 s
now, we know that
Impulse = ∫Fdt = ∫(   600 - 200000t ).dt
which gives us
I = 1.8 Ns
Hope this helps 
3 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 18 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details