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`        a bullet fired from a gun was given by f equals to 600 - 2 into 10 ^ fees in Newtons and 30 seconds the falls on the budget becomes zero as soon as the Bala what is the average impulse imparted to the bullet `
3 months ago

Arun
23546 Points
```							F = 600 - 2 * 10⁵t0 = 600 - 2 * 10⁵ tt = 600 / (2 * 10⁵)t = 3 * 10⁻³ st = 3 millisecondsTime taken by bullet to leave the barrel is 3 millisecondsF.dt = (600 - 2* 10⁵t).dtJ = [600t - (2 * 10⁵ t²/2)]J = [600*(3*10^-3) - (2 * 10^5 * (3 * 10^-3)^2 / 2)]J = 0.9 NsImpulse imparted to bullet is 0.9 Ns
```
3 months ago
Vikas TU
10083 Points
```							Dear student Above ans is incorrect The force will become zero in amount of time 't'so,F =   600 - 200000t = 0ort = 600 / 200000thus,t = 3 x 10 -3 snow, we know thatImpulse = ∫Fdt = ∫(   600 - 200000t ).dtwhich gives usI = 1.8 NsHope this helps
```
3 months ago
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