A BREAKING STRESS OF THE MATERIAL OF A WIRE IS 10 2 N/M 2 . THE MAXIMUM LENGTH OF THE WIRE FOR WHICH IT BREAKS UNDER ITS OWN WEIGHT WILL BE (DENSITY OF MATERIAL IS 2 X 10 3 KG/M 3 )?

Question

Vasantha Kumari · Answer

Yash Chourasiya · Answer

Dear Student

Here the weight of the wire will be ALρg
Stress due to its weight = W/A = Lρg
Therefore, Breakdown Stress = Lρg
8 * 10⁶ = L * 2*10⁶ * 9.8
L = 40*10^-2 m

I hope this answer will help you.
Thanks & Regards
Yash Chourasiya

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A BREAKING STRESS OF THE MATERIAL OF A WIRE IS 10 2 N/M 2 . THE MAXIMUM LENGTH OF THE WIRE FOR WHICH IT BREAKS UNDER ITS OWN WEIGHT WILL BE (DENSITY OF MATERIAL IS 2 X 10 3 KG/M 3 )?

A BREAKING STRESS OF THE MATERIAL OF A WIRE IS 10² N/M² . THE MAXIMUM LENGTH OF THE WIRE FOR WHICH IT BREAKS UNDER ITS OWN WEIGHT WILL BE (DENSITY OF MATERIAL IS 2 X 10³ KG/M³)?

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A BREAKING STRESS OF THE MATERIAL OF A WIRE IS 10 2 N/M 2 . THE MAXIMUM LENGTH OF THE WIRE FOR WHICH IT BREAKS UNDER ITS OWN WEIGHT WILL BE (DENSITY OF MATERIAL IS 2 X 10 3 KG/M 3 )?

A BREAKING STRESS OF THE MATERIAL OF A WIRE IS 102 N/M2 . THE MAXIMUM LENGTH OF THE WIRE FOR WHICH IT BREAKS UNDER ITS OWN WEIGHT WILL BE (DENSITY OF MATERIAL IS 2 X 103 KG/M3)?

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A BREAKING STRESS OF THE MATERIAL OF A WIRE IS 10² N/M² . THE MAXIMUM LENGTH OF THE WIRE FOR WHICH IT BREAKS UNDER ITS OWN WEIGHT WILL BE (DENSITY OF MATERIAL IS 2 X 10³ KG/M³)?