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a boy throws a ball in air in such a manner that when the ball is in its max height he throws another ball. if the balls are thrownafter the time difference of 1 s ; then what will be the height attain by them:

ayush , 7 Years ago
Grade 11
anser 1 Answers
Saurabh Koranglekar

Last Activity: 4 Years ago

u=0 m/s

t=1 second

time of ascend,

t=u/g

1=u/9.8

9.8 m/s\

maximum height reached, h=u^2/2g

h=(9.8)^2/2×9.8=4.9 m

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