a boy throws a ball in air in such a manner that when the ball is in its max height he throws another ball. if the balls are thrownafter the time difference of 1 s ; then what will be the height attain by them:
ayush , 7 Years ago
Grade 11
1 Answers
Saurabh Koranglekar
Last Activity: 4 Years ago
u=0 m/s
t=1 second
time of ascend,
t=u/g
1=u/9.8
9.8 m/s\
maximum height reached, h=u^2/2g
h=(9.8)^2/2×9.8=4.9 m
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