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```
a boy of weight 25kg slide sdown a rope hanging from the branch of the tree.if the force of friction against him is 50N,the boys acceleration is?
a boy of weight 25kg slide sdown a rope hanging from the branch of the tree.if the force of friction against him is 50N,the boys acceleration is?

```
4 years ago

Vikas TU
14149 Points
```							Simply balance the forces along with friction force.Therfore,F – f = ma250 – 50 = 25aa = 200/25 =  40/5 = 8 m/s^2
```
4 years ago
MVRChaitanya
13 Points
```							by applying dyanamic equation F-fk=mamg-50=25a250-50=25a200/25=aso acceleration=8metre/second square.40/5=aa=8m/sec2
```
2 years ago
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