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A body traverses 128 m in first four second and 72m in the next six second. If the acceleration remains uniform,then what will be the distance the body traversed after next two second?
Your question should read as:What is the acceleration of a body moving 16m in 4s and moving 9m in 3s with uniform acceleration?We shall take rectilinear motion with the equation of motion as follows.x = ut +1/2 at^2,where a is uniform acceleration and u is initial (t=0s) velocity.In case 1 x=16m and t=4s. Therefore, 16=4u+1/2 a(4)^2=4u+8a or 4=u+2a…………….(1)For second case,quite similarly, 3=u+1.5a………………………………………………………..(2)Eq(1)-Eq(2) gives a=2m/s^2.
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