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A body of mass 100g is moving with a velocity of 10m/s along the positive x-direction. At time t=0, when the body is at x=0, a constant force of 0.8N acting along the negative x-direction is applied on the body for 5sec. At t=3sec, position of the body in mts is

A body of mass 100g is moving with a velocity of 10m/s along the positive x-direction. At time t=0, when the body is at x=0, a constant force of 0.8N acting along the negative x-direction is applied on the body for 5sec. At t=3sec, position of the body in mts is

Grade:12th pass

1 Answers

Vikas TU
14149 Points
7 years ago
We get retardation here,
a = – 0.8/0.1 = 8 m/s^2.
final velocity at t=5s,
v = 10i -8i * 5
  = 10i – 40i
  = -30i
Now at t=3 apply 2nd law of eqn. and get the value of x.

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