A body of mass 0.5 kg travels in a straight linr with velocity v=ax 3/2 where a = 5m -1/2 s -1. what is the work done by the net force during its displacement from x=0 to x=2m?

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Susmita · Answer

v=ax 3/2 differentiate wrt x. dv/dt=(3a/2)x 1/2 (dx/dt)=(3a/2)x 1/2 v=(3a 2 /2)x 2 force F=mdv/d Work done dW=Fdx Integrate from 0 to 2. W=(a 2 m/2)8=4a 2 m=4*(5 2 )*0.5=50J

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A body of mass 0.5 kg travels in a straight linr with velocity v=ax 3/2 where a = 5m -1/2 s -1. what is the work done by the net force during its displacement from x=0 to x=2m?

A body of mass 0.5 kg travels in a straight linr with velocity v=ax^3/2 where a = 5m^-1/2s^{-1. what is the work done by the net force during its displacement from x=0 to x=2m?}

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A body of mass 0.5 kg travels in a straight linr with velocity v=ax 3/2 where a = 5m -1/2 s -1. what is the work done by the net force during its displacement from x=0 to x=2m?

A body of mass 0.5 kg travels in a straight linr with velocity v=ax3/2 where a = 5m-1/2s-1. what is the work done by the net force during its displacement from x=0 to x=2m?

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A body of mass 0.5 kg travels in a straight linr with velocity v=ax^3/2 where a = 5m^-1/2s^{-1. what is the work done by the net force during its displacement from x=0 to x=2m?}