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A body moves 6m north 8 metre east and 10 metre vertically upward what is the resultant displacement from initial position


one year ago

Arun
25211 Points
							Let us take positive x axis in east.Then x component of displacement is 8 m.We take positive y axis in north. Then,y component of displacement is 6 m.We take positive z axis in vertically upward direction. This givesz component of displacement is 10 m.The displacement vector is (8,6,10) mThe magnitude of this vector is (64+36+100)^(1/2)=(200)^(1/2)=10 sqrt 2.

one year ago
Khimraj
3007 Points
							When you travel 6m North and 8m East, in 2 dimensions the resultant vector by Pythagoras theorem is 10m.From that point it travels 10m upwards which again forms a right angle triangle in a different plan from the resultant vector whose magnitude is also 10mTherefore again applying Pythagoras theorem, root of 10^2 + 10^2 = 10$\sqrt{2}$

one year ago
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