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A body is thrown up with the velocity of 15 metre per second then the maximum height attained by the body is
Dear student Maximum height of a vertically projected body is given by h=u^2/2g . for derivation see the other answer.So the answer will be h= 15^2/2g= 225/20 (taking g = 10 m/s^2)= 11.25 m RegardsArun (askIITians forum expert)
Maximum height of a vertically projected body is given by h=u^2/2g . for derivation see the other answer.
So the answer will be h= 15^2/2g
= 225/20 (taking g = 10 m/s^2)
= 11.25 m
Regards
Arun (askIITians forum expert)
Maximum height is given by, h=u2/2g, where h is maximum height, u is initial velocity and g is acceleration due to gravity.So, Maximum Height, h=152/2g =225/2×10. (g=10m/s2) =11.25 m
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