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A body is projected vertically upwards. If t1 and t2 be the times at which it as height h above the point of projection while ascending descending respectively then value of h in t1 and t2
Apply simple Newton’s second law of equation,h = ut – ½ gt^2Now this is aquadratic in t time.ssolve it as quadratic and get 2 values of t .i.e. t1 and t2.And then mulitply them that is t1t2 and equate it to 2h/g.get h value.
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