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A body is projected vertically up with u.its velocity at half of its height is

veenagathri , 8 Years ago
Grade 11
anser 2 Answers
Abhinav
hmax = u2sin2\Theta​​/ 2g
when the body at half of its hmax, height = u2sin2\Theta​​/4g
here 
\Theta=90 
u2hmax4g, u=sq.root of hmax4g
ApprovedApproved
Last Activity: 8 Years ago
Lohith
Consider 3rd equation of kinematics V2 - u2 = 2gh From this h = u2/2g For h/2 = u2/4gNow substitue in above equationV2 = u2 -((2g*u2)/4g)Cancel g and 2 V2 = u2 - u2/2V2 = u2/2There fore v = u/ sqr root of 2 (Note v2 means v square and u2 means u square)
Last Activity: 8 Years ago
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