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A body is projected horizontally from a point above the ground. the motion of the body is described the equations x=2 and y=5t^2, where x and y are the horizontal and vertical displacements (in m) respectively at time t. What is the magnitude of the velocity of the body 0.2 seconds after it is projected?​

Yachna Saxena , 6 Years ago
Grade 11
anser 1 Answers
Aditya Gupta

Last Activity: 6 Years ago

we see that x coordinate remains constant. which means that the flight of the object is vertical. so, its velocity will only have a vertical component.
now, v= dy/dt= 10t
at t= 0.2, v= 10*0.2= 2m/s
kindly approve :)
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