A body is projected horizontally from a point above the ground. the motion of the body is described the equations x=2 and y=5t^2, where x and y are the horizontal and vertical displacements (in m) respectively at time t. What is the magnitude of the velocity of the body 0.2 seconds after it is projected?

Question

A body is projected horizontally from a point above the ground. the motion of the body is described the equations x=2 and y=5t^2, where x and y are the horizontal and vertical displacements (in m) respectively at time t. What is the magnitude of the velocity of the body 0.2 seconds after it is projected?​

Aditya Gupta · Answer

we see that x coordinate remains constant. which means that the flight of the object is vertical. so, its velocity will only have a vertical component. now, v= dy/dt= 10t at t= 0.2, v= 10*0.2= 2m/s kindly approve :)

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