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Grade 11General Physics

A body falls freely from the top of a tower . It covers 36% of the total height in the last second before striking the ground level. Find the height of tower?

Profile image of keerthi
8 Years agoGrade 11
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3 Answers

Profile image of Arun
8 Years ago
  Let H be the height of the building and t be the time to fall through this height H. 

Then H = ½ g t^2 = 5 t^2. ----------------- (1) 

In (t-1) second the distance traveled is 1 - 0.36 H = 0.64 H. 

0.64 H = 5 (t-1)^2.---------------------------(2) 

(2) / (1) gives 0.64 = (t-1)^2/ t^2 

Or 0.8 = (t-1) / t 

Solving we get t= 5 second. 

Using (1) we get H = 125 m.
Profile image of Upendra Yadav
8 Years ago
 Let H be the height of the building and t be the time to fall through this height H. 

Then H = ½ g t^2 = 5 t^2. -- (1) 

In (t-1) second the distance traveled is 1 - 0.36 H = 0.64 H. 

0.64 H = 5 (t-1)^2.------(2) 

on doing  (2) / (1)we get 
    0.64 = (t-1)^2/ t^2 

Or 0.8 = (t-1) / t 

Solving we get t= 5 second. 

Using (1) we get H = 125 m
Profile image of Sagar
6 Years ago
Answer :- Height of the tower = 122

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