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A body falls freely from the top of a tower . It covers 36% of the total height in the last second before striking the ground level. Find the height of tower?
Let H be the height of the building and t be the time to fall through this height H. Then H = ½ g t^2 = 5 t^2. ----------------- (1) In (t-1) second the distance traveled is 1 - 0.36 H = 0.64 H. 0.64 H = 5 (t-1)^2.---------------------------(2) (2) / (1) gives 0.64 = (t-1)^2/ t^2 Or 0.8 = (t-1) / t Solving we get t= 5 second. Using (1) we get H = 125 m.
Let H be the height of the building and t be the time to fall through this height H. Then H = ½ g t^2 = 5 t^2. -- (1) In (t-1) second the distance traveled is 1 - 0.36 H = 0.64 H. 0.64 H = 5 (t-1)^2.------(2) on doing (2) / (1)we get 0.64 = (t-1)^2/ t^2 Or 0.8 = (t-1) / t Solving we get t= 5 second. Using (1) we get H = 125 m
Answer :- Height of the tower = 122
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