A body falls freely from the top of a tower . It covers 36% of the total height in the last second before striking the ground level. Find the height of tower?

Question

Arun · Answer

Let H be the height of the building and t be the time to fall through this height H.

Then H = ½ g t^2 = 5 t^2. ----------------- (1)

In (t-1) second the distance traveled is 1 - 0.36 H = 0.64 H.

0.64 H = 5 (t-1)^2.---------------------------(2)

(2) / (1) gives 0.64 = (t-1)^2/ t^2

Or 0.8 = (t-1) / t

Solving we get t= 5 second.

Using (1) we get H = 125 m.

Upendra Yadav · Answer

Let H be the height of the building and t be the time to fall through this height H.

Then H = ½ g t^2 = 5 t^2. -- (1)

In (t-1) second the distance traveled is 1 - 0.36 H = 0.64 H.

0.64 H = 5 (t-1)^2.------(2)

on doing (2) / (1)we get

0.64 = (t-1)^2/ t^2

Or 0.8 = (t-1) / t

Solving we get t= 5 second.

Using (1) we get H = 125 m

Sagar · Answer

Answer :- Height of the tower = 122

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A body falls freely from the top of a tower . It covers 36% of the total height in the last second before striking the ground level. Find the height of tower?

A body falls freely from the top of a tower . It covers 36% of the total height in the last second before striking the ground level. Find the height of tower?

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