A body falling from a vertical height of 10 pierces through a distance of 11 in sand. It faces an average retardation in sand equal to (g=acceleration due to gravity)

Question

Rohan · Answer

So what? the body is in sand nothing else it only stopped due to the friction but the body while falling down obtained kinetic energy and went 10m deep but more 1m was due to its mass.it went more deep hence astonishing us for its answer

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A body falling from a vertical height of 10 pierces through a distance of 11 in sand. It faces an average retardation in sand equal to (g=acceleration due to gravity)

A body falling from a vertical height of 10 pierces through a distance of 11 in sand. It faces an average retardation in sand equal to (g=acceleration due to gravity)

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A body falling from a vertical height of 10 pierces through a distance of 11 in sand. It faces an average retardation in sand equal to (g=acceleration due to gravity)

A body falling from a vertical height of 10 pierces through a distance of 11 in sand. It faces an average retardation in sand equal to (g=acceleration due to gravity)

1 Answers

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