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A bodt of mass m is launched up ona rough inclined plane making an angle 45 with horizontal . if the time of ascent is half of the time of desent ,the frictional coefficient between plane and body is

uday surya , 5 Years ago
Grade 9
anser 1 Answers
Vikas TU

Last Activity: 5 Years ago

Hiii 
Time taken to cover upward = Tu
Time taken to cover downward = Td
Td = 2Tu
We know that 
S = VoTu - ½ aTu^2 (Upward Motion)
S= ½ a Td^2
solving this , you will get 
Upper acceleration = 4 * below acceleration
Using Newons second law of motion
mau = mgsinQ + mew*mgcosQ
mad = mgsinQ – mew*mgcosQ
putting the value and solving you will get 
mew = 3/5
 

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