Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        a block  of  mass  200 kg is  kept on a  rough  horizontal  surface. It just begins to move when a force of  200 kg  wt. is applied  .calculate  the  coefficient  of static  friction.`
2 years ago

Arun
23506 Points
```							Dear Rudra Mass = 200 kg.Force = 200 N.Coefficient of static friction = ( ? )It means we need to calculate how much resistance to friction the block is on the rough surface.So Friction = Coefficient of static friction × Mass × Gravitational Acceleration200 = 200 × 10 × coefficient of static friction200 / 2000 = Coefficient of static frictionCoefficient of static friction = 0.1   RegardsArun (askIITians forum expert)
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on General Physics

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 18 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions