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We have, coefficient of static friction, µs = 0.4
Mass, m = 2 kg
Force applied, F = 2.5 N
Maximum static frictional force, fmax= µs × m × g = 0.4 × 2 × 9.8
=> fmax = 7.84 N
Since, the applied force is less than the maximum static frictional force, the frictional force on the block is equal to the applied force = 2.5 N. This is according to the fact that static friction is a self adjusting force.
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