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`        A block B of mass 5kg is placed on another block A of mass 10kg, which rests on a smooth horizontal surface. If u=0.4 between A and B and a force F=40N is applied on block B, the acceleration of A is :​a) 3m/s2​b) 2 m/s2​c) 4 m/s2​d) 8/3 m/s2`
2 months ago

Shivam Agrawal
14 Points
```							Assume the force on Block B to be applied in right Direction. Let that Force be F1= 40N Frictional Force acting between the two block will act in the opposite direction i.e is left direction. Let this force be F2.F2= u* (mass of B) * g    = 0.4*5*10F2 = 20N This force will create acceleration in Block A. We know Force = Mass * Acceleration F2 = (mass of A)* (Acceleration of A)20 = 10 *( Acceleration of A)Acceleration of A = 2m/s2.
```
2 months ago
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• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions