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A balloon starts ascending with a constant acceleration for 5 sec. A stone is thrown from the balloon and it reaches the ground in 5 sec. Calculate the velocity with which the balloon starts rising upwards. Ans :12.5 m/s

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4 months ago

Arun
25210 Points
```							Analysis of situation: t = 0 is the time when the balloon started rising up. At t = 0, when the packet is dropped, the balloon is moving up with velocity v = 0 + at 0​   = at 0​  . Hence, initial velocity of the packet will be v 0​  =at 0​   (upward). As the balloon has started rising upwards with constant acceleration a, so after t 0​   seconds, its height from the ground is y 0​  = 21​  at 02​  .For packet: s = ut - 21​  gt 2 ⇒ − 21​  at 02​   = at 0​  t− 21​  gt 2  ⇒ gt 2 −2at 0​  t−at 02​  =0Solving the quadratic equation, we get t =  gat 0​  ​  [1+ 1+ ag​  ​  ]
```
4 months ago
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