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Grade: 12th pass
        A balloon Rises from rest on the ground with constant acceleration 1 m per second square a stone is dropped when the balloon has Raj into a height of 39.2 metre the time taken by the stone to reach the ground nearly
9 months ago

Answers : (1)

Arun
13770 Points
							
Dear Anuj
 
The velocity of the balloon at the height 39.2 is 
v = sqrt(2aH) = sqrt(2*1*39.2) = sqrt(78.4) 

Initial velocity of the stone at height 39.2 is u = sqrt(78.4) upwards. 
39.2 = sqrt(78.4) *t - (1/2)* t²


The time taken by the stone to reach the ground can be obtained by solving the above quadratic. 
 
Hope it helps
 
Regards
Arun (askIITians forum expert)
9 months ago
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