0

Guest

Courses New

A balloon rises from rest on the ground with an acceleration g/8. A stone is dropped from the balloon when it is at a height H. Calculate the time taken by the stone to reach the ground.

A balloon rises from rest on the ground with an acceleration g/8. A stone is dropped from the balloon when it is at a height H. Calculate the time taken by the stone to reach the ground. 

Grade:11

1 Answers

Avishek Bhagat
askIITians Faculty 71 Points
3 years ago
Dear Student,
answer to the problem is

V2= U2 + 2×g/8×H. (U = 0)

V = 1/2× √gh

Stone is released at height h with initial velocity ( - 0•5√gH)

H= Ut + 0•5gt2

H= -0•5√gHt + 0•5gt2

0•5gt2 - 0•5√gH t -H =0

t2-√H/g t - 2H/g = 0

t =( √H/g +- ✓H/g +8H/g)/2 =(√H/g +-✓9H/g)/2

t = either 2√H/g or -√H/g

negative value of time may be rejected

t =2√H/g


askIITians Expert
Yuvraj Singh

Think You Can Provide A Better Answer ?

Other Related Questions on General Physics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More