Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        a balloo starts rising from ground from rest with an upward acceleration of 2 ms-2 . Just after 1 second, a stone is dropped from it.The time taken by stone to strike the ground is nearly:1)0.3 secs2)0.7 secs3)1 secs4)1.4 secs`
5 years ago

bharat bajaj
IIT Delhi
122 Points
```							After 1 second,The speed of stone = The speed of balloon at that instantDistance from ground when stone is dropped = 1/2. 2 = 1 mSpeed of stone = 2.1 = 2 m/s upwardsg = 10v = u + ats = ut + 1/2 a t^2-1 = 2t - 5t^25t^2 - 2t - 1 = 0t = 2 + v24 / 10t = 0.7 sOption 2) is correct.ThanksBharat BajajIIT Delhiaskiitians faculty
```
5 years ago
Arun Kumar
IIT Delhi
256 Points
```							Hello$\\ \\v_{after \,1 \,sec}=2m/s \\=>h_{after \,1 \,sec}=1/2*2*1^2=1m \\T=2v/g+time to fall from 1 m with \\ initial downward velocity of 2m/s \\1=2t+5t^2 \\=>t={-2 + \sqrt{24} \over 10} \\please evaluate yourself$Thanks & RegardsArun KumarBtech, IIT DelhiAskiitians Faculty
```
5 years ago
Think You Can Provide A Better Answer ?

Other Related Questions on General Physics

View all Questions »

Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

Course Features

• 18 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions