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Grade: 9

                        

a ball thrown upwards return to the ground with the initial speed of u.the ball is at a height of 80m at two times,the time interval being 6 seconds . find u by assuming g = 10m/s

3 years ago

Answers : (1)

Arun
24737 Points
							
S = 80 metres
a = g = –10 m/s^2
using the equations
S = u*t + (1/2) gt^2
80 = u* t + (1/2) ( –10) t^2
5t^2 –ut +80  = 0
t = [u + \sqrt(u^2 –1600)  ]/10
& t = [u – \sqrt(u^2 –1600)  ]/10
[u + \sqrt(u^2 –1600)  ]/10 – [u  –\sqrt(u^2 –1600)  ]/10  = 6
hence
\sqrt(u^2 –1600) = 30
(u^2 –1600) = 900
u^2 = 2500
u = 50 m/s
hope it helps
3 years ago
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