×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

a ball thrown upwards return to the ground with the initial speed of u.the ball is at a height of 80m at two times,the time interval being 6 seconds . find u by assuming g = 10m/s


3 years ago

Arun
24737 Points
							S = 80 metresa = g = –10 m/s^2using the equationsS = u*t + (1/2) gt^280 = u* t + (1/2) ( –10) t^25t^2 –ut +80  = 0t = [u + $\sqrt$(u^2 –1600)  ]/10& t = [u – $\sqrt$(u^2 –1600)  ]/10[u + $\sqrt$(u^2 –1600)  ]/10 – [u  –$\sqrt$(u^2 –1600)  ]/10  = 6hence$\sqrt$(u^2 –1600) = 30(u^2 –1600) = 900u^2 = 2500u = 50 m/shope it helps

3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on General Physics

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 18 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions