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A ball thrown up in a vacuum returns after 12 seconds.Its position after 4 seconds will be the sameas after:(a) 2 second (b) 6 second(c)8second(d)10second

A ball thrown up in a vacuum returns after 12 seconds.Its position after 4 seconds will be the sameas after:(a)  2 second (b) 6
second(c)8second(d)10second

Grade:11

1 Answers

Harshit Singh
askIITians Faculty 5963 Points
3 years ago
Dear Student

total time = 12sec
for t=12 sec, displacement y=0
so
ut=.5xgxt2
u=60 m/s
for t= 4 sec, y=160m
let the required time be t
y=160 @time =t
by y=ut – (1/2)gt2
t= 8 sec


Thanks

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