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A ball projected with velocity of10 m/s at angle of 30° with horizontal just clears two verticals poles each of height 1m find separation between the poles

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2 years ago

Shubham Pathy
19 Points
```							We know equation of trajectory of a projectile y=xtanm  - (gx^2/2(ucosm)^2).     Here m is angle of projection. Substituting y=1and m=30° and g=10We get (x^2)/15  -x/√3  + 1=0 => X=2.29 ,6.52 So, distance from first hurdle = 2.29metreDrDistance from second hurdle = 6.52 metre So distance between the hurdles ,d=6.52-2.29=4.23metre
```
2 years ago
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