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A ball is thrown with velocity v it reaches maximum height.if one wishes to triple the maximum height then the ball should be thrown with what velocity

Kisalay , 7 Years ago
Grade 11
anser 4 Answers
Vikas TU

Last Activity: 7 Years ago

We definitely realize that , 
Height(h) = u2/2g 
In any case, its speed is v 
At that point Height (h) = v2/2g 
    v = starting speed 
    g = increasing speed because of gravity 
    h2/h1 = v1 2/v2 2 
    √( h2/h1) = v1/v2 
    v2√( h2/h1) = v1 
    h2 = 3 h1 
    v2√3 h1/h1 = v1 
    v1 = √3 v2 

User

Last Activity: 7 Years ago

Root3v must be the answer because according to question it is given that the when the height is tripled than velocity is unknown but we know rh

gavini haritha

Last Activity: 7 Years ago

We know that h is directly proportional to u^2. Then h/3h=u^2/x (where x the velocity when height is 3h),by this we get x=3u^2

Omed prakash

Last Activity: 7 Years ago

H1= Vo2/2g and 3H1= v2/2gAgain divided both equation H1/3H1=Vo2/v2 Vo/v= squareroot of H1/3H1Then v= square root of 3 Vo

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