A ball is thrown veticaly upward with an initial speed of 20m/s calculat 1)the time taken to return the acceleration. 2)the maximum night reach.

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Dhrishi patel · Answer

Total time of flight =2u/g=2*20x10=4s Max height reach=u square/2g=20m Since dear student it was jst a formula for total time of flight i.e time of ascent +time of descent

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A ball is thrown veticaly upward with an initial speed of 20m/s calculat 1)the time taken to return the acceleration. 2)the maximum night reach.

A ball is thrown veticaly upward with an initial speed of 20m/s calculat 1)the time taken to return the acceleration. 2)the maximum night reach.

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A ball is thrown veticaly upward with an initial speed of 20m/s calculat 1)the time taken to return the acceleration. 2)the maximum night reach.

A ball is thrown veticaly upward with an initial speed of 20m/s calculat 1)the time taken to return the acceleration. 2)the maximum night reach.

1 Answers

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