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`        A ball is thrown vertically upwords from a bridge with an intial velocity 4.9 m/s it stricks  the the after 2sec if accel due to gravity 9.8m/s What is the height of bridgeWith which velocity does the ball strike the water`
2 years ago

Arun
24740 Points
```							Dear Vijay V² = u² - 2*g*s0 = 4.9² - 2*9.8 * sS = 4.9 * 4.9/2* 9.8 = 4.9/4 = 1.225 m NowV = u - gt0 = 4.9 - 9.8 tt = 0.5 sec Now H = ½* 9.8 * 1.5²H = 4.9 * 2.25 = 11.025 m Hence height of bridge = 11.025 - 1.225 = 9.8 m  RegardsArun (askIITians forum expert)
```
2 years ago
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