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Grade: 12th pass
        A ball is thrown vertically upwords from a bridge with an intial velocity 4.9 m/s it stricks  the the after 2sec if accel due to gravity 9.8m/s What is the height of bridgeWith which velocity does the ball strike the water
5 months ago

Answers : (1)

Arun
11425 Points
							
Dear Vijay
 
V² = u² - 2*g*s
0 = 4.9² - 2*9.8 * s
S = 4.9 * 4.9/2* 9.8 = 4.9/4 = 1.225 m
 
Now
V = u - gt
0 = 4.9 - 9.8 t
t = 0.5 sec
 
Now
 
H = ½* 9.8 * 1.5²
H = 4.9 * 2.25 = 11.025 m
 
Hence height of bridge = 11.025 - 1.225 = 9.8 m
 
 
Regards
Arun (askIITians forum expert)
 
5 months ago
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