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A ball is thrown vertically upward from the top of the tower with a speed of 40m/s returns back to the ground level in 10s .The height of the tower is
A ball is thrown vertically upward from the top of the tower with a speed of 40m/s returns back to the ground level in 10s .The height of the tower is

```
4 years ago

PASUPULETI GURU MAHESH
126 Points
```							Top of the tower u=40 v=u-gtt=40/10=4 secmaximum height h= ut -1/2 gt2 you get height ball reach from the tower.and calculate the height from the maximum height      H=ut+1/2gt2initial at maximum height u=0then H =1/2gt2then the tower height = H-hyou calculate and get the height of the tower Thank you.Be smile bye
```
4 years ago
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