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Kapil soni Grade: 11
        A ball is thrown upward with initial velocity u at a height of 80m at 2 times The time interval being 6 sec find u
one year ago

Answers : (3)

SAHIL
3783 Points
										
INITIAL SPEED = u
HEIGHT= 80 M
TIME OF ASCEND T1:
0=u-gT1
 
TIME OF DESCEND T2:
0=u-gT2
 
SO T1 + T=6
2u/g = 6
u = 29.4 m/s 
 
Thanks
one year ago
Ayush A Patnaik
33 Points
										
a = g = -10 m/s^(2)
s = +80 m

s = ut + (1/2) x g x t^(2) ; where t is time and a is acceleration due to gravity

80 = ut + (1/2) x -10 x t^(2)
 
80 = ut – 5{t^(2)}

5{t^(2)} – ut + 80 = 0

use the quadratic equation to solve for ‘t’

t = {u + [square root] (u^2 – 1600) }/10 --- eq.(i)    &   {u – [square root](u^2 – 1600)}/10 --- eq.(ii)

eq.(i) + eq.(ii) = 6

solving both, you get 

{[square root](u^2 – 1600)}/5  = 6

[square root](u^2 – 1600) =  30

u^2 – 1600 = 900

u^2 = 2500

u = +50 or -50

therefore, u = +50 m/s 
 
10 months ago
Ayush A Patnaik
33 Points
										
a = g = -10 m/s^(2)
s = +80 m

s = ut + (1/2) x g x t^(2); where t is time and a is acceleration due to gravity

80 = ut + (1/2) x -10 x t^(2)
 
80 = ut – 5{t^(2)}

5{t^(2)} – ut + 80 = 0

use the quadratic equation to solve for ‘t’

t = {u + [square root] (u^2 – 1600) }/10 --- eq.(i)    &   {u – [square root](u^2 – 1600)}/10 --- eq.(ii)

eq.(i) + eq.(ii) = 6

solving both, you get 

{[square root](u^2 – 1600)}/5  = 6

[square root](u^2 – 1600) =  30

u^2 – 1600 = 900

u^2 = 2500

u = +50 or -50

therefore, u = +50 m/s 
 
10 months ago
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