A ball is thrown eastwards across a level ground.A wind blows horizontally tothe east and assume that the effect of wind is to provide a constant force towards the east,equal in magnitude to the weight of the ball.find the angle (with horizontal ) at which the ball should be projected for maximum range? pls as quickly!!!!!!

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here the acceleration is g both horizontally (eastward) and vertically (downward) time of flight = t = 2usinθ / g horizontally s = ut + (0.5)at² s = ucosθ(2usinθ)/g + (0.5)g[2usinθ / g]² s = (1/g)[u²sin2θ + 2u²sin²θ] for maximum s => ds/dθ = 0 => (u²/g)[cos2θ.2 + 4sinθcosθ] = 0 => [cos2θ + sin2θ] = 0 or tan2θ = -1 => θ = 135/2 = 67.5° also the max range R = 2.555(u²/g) Ans: angle θ the ball should be thrown so that it travels the maximum horizontal distance = 67.5° hope this helps