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Grade 12th passGeneral Physics

A ball is released from top of tower of height ‘h’ metre.It takes T time to reach to the ground. What is the position of the ball in T/3 sec.
(A) h/9 M from ground (B) 7h/9 M from ground
(C) 8h/9 M from ground (D) 17h/18 M from the ground

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Profile image of Faiz Anwar
8 Years agoGrade 12th pass
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1 Answer

Profile image of Khimraj
8 Years ago
According to above condition
h = (½)*gT2
Let at T/3 postion of ball is at height H from ground.
Then
h-H = (½)*g(T/3)2
So,
h- H = h/9.
Then H = 8h/9 M from ground.
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