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Grade: 12
        
a ball is projected with a speed u at an angle theta to the horizontal. the range R of the projectile is given by 
R=u^2 sin2theta/g
for which value of theta the range will be maximumfor a given speed of projectile.
(g is constant)
2 years ago

Answers : (6)

vindhya
50 Points
							
please help. its very urgent
2 years ago
erra akhil
208 Points
							
For 45degrees the range is maximum
 
2 years ago
erra akhil
208 Points
							
Dear Vindhya,
u2sin2θ/g=Range-----eq.1
since maximum value of sinθ=1 and it is possible only when θ=90
here in eq.1,
for sin2θ to  be maximum, 2θ=90;
which implies θ=45 in this case.
Hence range is maximum when theta is 45degrees 
2 years ago
erra akhil
208 Points
							
Approve my answer helped you.
 
2 years ago
vindhya
50 Points
							
thanks but options are given as-
  1. pi/2 radian
  2. pi/3 radian
  3. pi/4 radian
  4. pi/6 radian
  5.  
2 years ago
vindhya
50 Points
							
so, is the answer pi/4 radian ?
2 years ago
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