Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A ball falls from a height of 5m and strikes the roof of a lift. If at the time of collision lift is moving in upward direction with velocity of 1m/s then the velocity with which the ball rebounds after collision will be`
one year ago

Arun
23045 Points
```							Dear student I am getting my answer as 12m/sec. Please lef me know if this is correct then I will share my solution Hope it helps RegardsArun (askIITians forum expert)
```
one year ago
Akshay keshwani
10 Points
```							Please share the solution with explanation............................................................
```
one year ago
Krutarth
38 Points
```							MASS OF LIFT = M2                               MASS OF BALL = M1V1=(M2-M1)​​     +     2M2  U2       M2+M1            M2+M1                                                 M2>>M1V1=M2  U1       +     2M2  U2        M2                         M2 =U1+2U2 h=5m     ,    v2-u2=2gh           0  -u12 =2x10x5...u1=10             v1 = 10+2x1(u1+2u2)                 =12m/s
```
one year ago
Think You Can Provide A Better Answer ?

## Other Related Questions on General Physics

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 18 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions