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A ball falls from a height of 5m and strikes the roof of a lift. If at the time of collision lift is moving in upward direction with velocity of 1m/s then the velocity with which the ball rebounds after collision will be

Akshay keshwani , 6 Years ago
Grade 11
anser 3 Answers
Arun

Last Activity: 6 Years ago

Dear student
 
I am getting my answer as 12m/sec. Please lef me know if this is correct then I will share my solution
 
Hope it helps
 
Regards
Arun (askIITians forum expert)

Akshay keshwani

Last Activity: 6 Years ago

Please share the solution with explanation............................................................

Krutarth

Last Activity: 6 Years ago

MASS OF LIFT = M2                               MASS OF BALL = M1
V1=(M2-M1)​​         2M2  U2
       M2+M1            M2+M1
 
                                                M2>>M1
V1=M2  U1       +     2M2  U2
        M2                         M2
 
=U1+2U2
 
h=5m     ,    v2-u2=2gh
           0  -u12 =2x10x5...u1=10
             v1 = 10+2x1(u1+2u2)
                 =12m/s

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